Kod
<table border="1" width="100%">
<tr>
<td>
<p align="center">
<img border="0" [b]src="pic/<? echo $nr; ?>.jpg"[/b] width="500" height="375"></td>
</tr>
</table>
<table border="1" width="100%">
<tr>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=1">[/b]
<img border="0" src="pic/1.jpg" width="150" height="112"></a></td>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=2"[/b]>
<img border="0" src="pic/2.jpg" width="150" height="112"></a></td>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=3"[/b]>
<img border="0" src="pic/3.jpg" width="150" height="112"></a></td>
</tr>
</table>
<tr>
<td>
<p align="center">
<img border="0" [b]src="pic/<? echo $nr; ?>.jpg"[/b] width="500" height="375"></td>
</tr>
</table>
<table border="1" width="100%">
<tr>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=1">[/b]
<img border="0" src="pic/1.jpg" width="150" height="112"></a></td>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=2"[/b]>
<img border="0" src="pic/2.jpg" width="150" height="112"></a></td>
<td>
<p align="center">
<a target="_self" [b]href="index.php?nr=3"[/b]>
<img border="0" src="pic/3.jpg" width="150" height="112"></a></td>
</tr>
</table>
Po otwarciu strony widze tylko ikonki, nie ma żadnego głownego zdjecia. Jak tu ustawić pierwsze domyślne zdjęcie?
Jeszcze jedno z innej półki: po pobraniu danych z bazy danych MySQL, umiem wyświetlić dane w formie tabeli, która składa się z jednej kolumny. Chce by kolumn było 4. Poniżej fragment kodu:
Kod
<table>
<?php
$videolist = @mysql_query($select . $from . $where);
if (!$videolist) {
echo '</table>';
exit('<p>Video can not be load!!<br />'.
'Error: ' . mysql_error() . '</p>');
}
while ($vid = mysql_fetch_array($videolist)) {
$data = $vid['data'];
$zdjecie = $vid['photo'];
$tytul = $vid['titel'];
$link = $vid['link'];
echo "<tr valign='top'>\n";
echo "<img src='$zdjecie' width='80' height='60' >";
echo "<a href='index.php?videoId=$link' target='_parent'>".
"Added: $data" .
"<a href='index.php?videoId=$link' target='_parent'>PLAY NOW!</a>\n";
}
?>
</table>
<?php
$videolist = @mysql_query($select . $from . $where);
if (!$videolist) {
echo '</table>';
exit('<p>Video can not be load!!<br />'.
'Error: ' . mysql_error() . '</p>');
}
while ($vid = mysql_fetch_array($videolist)) {
$data = $vid['data'];
$zdjecie = $vid['photo'];
$tytul = $vid['titel'];
$link = $vid['link'];
echo "<tr valign='top'>\n";
echo "<img src='$zdjecie' width='80' height='60' >";
echo "<a href='index.php?videoId=$link' target='_parent'>".
"Added: $data" .
"<a href='index.php?videoId=$link' target='_parent'>PLAY NOW!</a>\n";
}
?>
</table>