Witam, uzywamtego samego kodu na innej stronie, i tam dziala (hosting ten sam), lecz na tej 2 stronie wyskakuje my blad:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/p143981/public_html/pages/1.html on line 18

Kod z page1.html:

[PHP] pobierz, plaintext 
<?php
 
    mysql_connect ("xxx", "xxx", "xxx");
    mysql_select_db ("p143981_website");
    mysql_query('SET NAMES \'utf8\'');
    mysql_query("SET NAMES utf8");
    mysql_query("SET CHARACTER SET utf8");
    mysql_query("SET collation_connection = utf8_polish_ci");
 
mysql_query("SET CHARSET utf8");
mysql_query("SET NAMES `utf8` COLLATE `utf8_polish_ci`"); 
 
 
$sql = "SELECT * " .
"FROM web_content " .
"WHERE id=1";
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_array($sql)){
?>
<table><tr><td><?php echo $row[content]; ?></td></tr></table>
<?php
}
?>
 
[PHP] pobierz, plaintext 

while($row = mysql_fetch_array($result)){

ma być

Niemożliwe

Tą linijkę:

[PHP] pobierz, plaintext 
$result = mysql_query($sql) or die(mysql_error());
[PHP] pobierz, plaintext 

zmień na:

[PHP] pobierz, plaintext 
$sql = mysql_query($sql) or die(mysql_error());
[PHP] pobierz, plaintext 

Cześć.



Pozdrawiam.