function getPoll($pollID){ $query = "SELECT * FROM polls LEFT JOIN pollAnswers ON polls.pollID = pollAnswers.pollID WHERE polls.pollID = " . $pollID . " ORDER By pollAnswerListing ASC"; //echo $query;jquery $pollStartHtml = ''; $pollAnswersHtml = '';
W tej 10 linijce pojawia się znany błąd :
"Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in"...