Kod
<?
$host = "localhost";
$log = "sendi16";
$pass = "polska";
$base = "sendi16";
$link = @mysql_connect("$host", "$log", "$pass");
mysql_select_db("$base");
$query = "SELECT * FROM user";
$result = mysql_query("$query");
$line = mysql_fetch_array($result);
?>
$host = "localhost";
$log = "sendi16";
$pass = "polska";
$base = "sendi16";
$link = @mysql_connect("$host", "$log", "$pass");
mysql_select_db("$base");
$query = "SELECT * FROM user";
$result = mysql_query("$query");
$line = mysql_fetch_array($result);
?>
Możecie mi wyjaśnić co w nim jest nie tak??
po uruchomieniu wyskakuje mi taki błąd:
Warning: MySQL: Unable to save result set in
c:apachehtdocslogowanie_phplogowanie_php2.php on line 16
Warning: Supplied argument is not a valid MySQL result resource in c:apachehtdocslogowanie_phplogowanie_php2.php on line 17
prosze o pomoc
z góry dzięki[/code]