mam taki kod

[PHP] pobierz, plaintext 
  1.     function callApi(acallback) {
  2.        // alert(acallback);
  3.       $.ajax({
  4.           url: acallback,
  5.           type: 'GET',
  6.           dataType: "jsonp",
  7.           jsonp: "callback",
  8.           jsonpCallback: "jsonpCallback2",
  9.           complete: function (response, responseCode) {
  10.               console.log(response); console.log(responseCode);
  11.           },
  12.           success: function (json) {
  13.               console.log(json);
  14.               var HotelName = "jakasnazwa";
  15.               ;
  16.               $.each(json, function (index, value) {
  17.                   var contentFromAPI = '<tr><td>' + this.ReservationId + '</td><td>' + HotelName + '</td><td>' + this.CheckInDate + '</td><td>' + this.Total + '</td><td>' + this.CreatedOn + '</td><td>' + this.Status + '</td></tr>';
  18.                   // alert(contentFromAPI);
  19.                   $("table.arrival tbody").append(contentFromAPI);
  20.               });
  21.  
  22.           },
  23.     error: function(response, status, err){
  24.  
  25.         console.log(response.status);
  26.  
  27.         if(response.status == 400){
  28.             console.log("Sorry, this is bad request!");
  29.         }
  30.         if(response.status == 601){
  31.             sessionTimedOut();
  32.         }
[PHP] pobierz, plaintext


Tylko, ze gdy dostaje error 400
[PHP] pobierz, plaintext 
  1. "NetworkError: 400 Bad Request 
[PHP] pobierz, plaintext


W konsoli nie ma mojego Sorry, 'this is bad request!'
Jak to ugryźc?

EDIT:
Response body
[PHP] pobierz, plaintext 
  1. {
  2.   "reason": "date(s) are invalid",
  3.   "code": 400
  4. }
[PHP] pobierz, plaintext


Wiem, ze moge poprostu sprawdzic czy code ==400, ale czy nie da sie tego zalatwic poprzez error?