Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 3 in D:\Studia\Programy\xampp\htdocs\praca\logowanie.php on line 89
Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 4 in D:\Studia\Programy\xampp\htdocs\praca\logowanie.php on line 93
Nie ma takiego uzytkownika w bazie
A oto skrypcik logowanie.php
<form action = 'logowanie.php' method = 'POST'> <Table border = 1> <tr> <font size = 3><b>Wprowadz dane aby sie zalogowac: </b></font><br /><br /> </tr> <tr> <td> <b> Login: </b> </td> <td> <input type = 'text' name = 'login' size = '40' maxlenght = '100' value = '<?php ?>' /> </td> </tr> <tr> <td> <b> Haslo: </b> </td> <td> <input type = 'password' name = 'haslo' size = '40' maxlenght = '100' value = '<?php ?>' /> </td> </tr> <tr> <td> <input type="reset" value="Reset"> </td> <td> <input type = 'submit' name ='log' value = 'Zaloguj'/> </td> </tr> </td> </tr> </Table> </table> </form> <?php $login = FALSE; }else{ $login = $_POST ['login']; } $haslo = FALSE; }else{ $haslo = $_POST ['haslo']; } if ($login && $haslo) { $sql="SELECT password FROM user WHERE Nick = '$login'"; $sql_login="SELECT Nick FROM user WHERE Nick = '$login'"; } if($login != $zmienna_login){ } elseif($md_haslo==$zmienna){ } else{ } } ?>