<?php
$connect = mysql_connect("localhost", "root", "") or
die ("sprawdź połączenie z serwerem. ");
$create = mysql_query("CREATE DATABASE IF NOT EXISTS moviesite")
or die(mysql_error());
mysql_select_db("moviesite");
// tworzenie tabeli
$movie = "CREATE TABLE movie (
movie_id int(11) NOT NULL auto_increment,
movie_name varchar(255) NOT NULL ,
movie_type tinyint(2) NOT NULL default 1,
movie_year int(4) NOT NULL default 1,
movie_leadactor int(11) NOT NULL default 0,
movie_director int (11) NOT NULL default 0,
PRIMARY KEY (movie_id),
KEY movie_type (movie_type.movie_year)
)";
$results = mysql_query($movie)
or die (mysql_error());
// tabela movitype*/
$movietype = "CREATE TABLE movietype (
movietype_id int(11) NOT NULL auto_increment,
movietype_lebel varchar(100) NOT NULL,
PRIMATY KEY (movietype_id)
)";

$results = mysql_query($movietype)
or die (mysql_error());

// utwórz tablele people
$people = "CREATE TABLE people (
people_id int(11) NOT NULL auto_increment,
people_fullname varchar(255) NOT NULL default 0,
people_isactor tinyint(1) NOT NULL default 0,
people_isdirector tinyint(1) NOT NULL default 0,
PRIMARY KEY (poeple_id)
)";
$results = mysql_query($people)
or die (mysql_error());

echo "poprawnie utworzono bazę danych filmów ";
?>

Something is wrong in your syntax obok '.movie_year) )' w linii 9

$connect = mysql_connect("localhost", "root", "")
or die ("sprawdz polączenie z bazą");
mysql_select_db("movisite");
$insert = "INSERT INTO movie (movie_id, movie_name, movie_type,".
"movie_year, movie_leadactor, movie_director)" .
"VALUES (1, 'bruce wszechmogacy', 5, 1999, 1, 2),".
"(2, 'zywot braiana', 4, 1697, 5, 6)";
$results = mysql_query($insert)
or die(mysql_error());

echo "Dane zostaty wstawione poprawnie!";
?>