hm, poniewaz zaczynam dopiero w php prosze o pomoc w ustawieniu skryptu wyliczajacego roznice pomiedzy dwoma datami:
moja strona istnieje xx lat xx miesiecy xx dni xx godzin
instrukcja scriptu free jest nastepujaca (aha nie zabardzo znam angielski):
[php:1:fb854c77a4]<?
// configure the base date here
$base_day = 11; // no leading "0"
$base_mon = 5; // no leading "0"
$base_yr = 2001; // use 4 digit years!
// get the current date (today) -- change this if you need a fixed date
$current_day = date ("j");
$current_mon = date ("n");
$current_yr = date ("Y");
// and now .... calculate the difference! :-)
// overflow is always caused by max days of $base_mon
// so we need to know how many days $base_mon had
$base_mon_max = date ("t",mktime (0,0,0,$base_mon,$base_day,$base_yr));
// days left till the end of that month
$base_day_diff = $base_mon_max - $base_day;
// month left till end of that year
// substract one to handle overflow correctly
$base_mon_diff = 12 - $base_mon - 1;
// start on jan 1st of the next year
$start_day = 1;
$start_mon = 1;
$start_yr = $base_yr + 1;
// difference to that 1st of jan
$day_diff = ($current_day - $start_day) + 1; // add today
$mon_diff = ($current_mon - $start_mon) + 1; // add current month
$yr_diff = ($current_yr - $start_yr);
// and add the rest of $base_yr
$day_diff = $day_diff + $base_day_diff;
$mon_diff = $mon_diff + $base_mon_diff;
// handle overflow of days
if ($day_diff >= $base_mon_max)
{
$day_diff = $day_diff - $base_mon_max;
$mon_diff = $mon_diff + 1;
}
// handle overflow of years
if ($mon_diff >= 12)
{
$mon_diff = $mon_diff - 12;
$yr_diff = $yr_diff + 1;
}
// the results are here:
// $yr_diff --> the years between the two dates
// $mon_diff --> the month between the two dates
// $day_diff --> the days between the two dates
// ****************************************************************************
// simple output of the results
print "The difference between <b>".$base_yr."-".$base_mon."-".$base_day."</b> ";
print "and <b>".$current_yr."-".$current_mon."-".$current_day."</b> is:";
print "<br><br>";
// this is just to make it look nicer
$years = "years";
$days = "days";
if ($yr_diff == "1") $years = "year";
if ($day_diff == "1") $days = "day";
// here we go
print $yr_diff." ".$years.", ";
print $mon_diff." month and ";
print $day_diff." ".$days;
?>[/php:1:fb854c77a4]
prosze o pomoc jak ten script ustawic z data wyjsciowa 1998.06.20 i jak go fizycznie "uruchomic" w html-u
Niestety nie znam php, HTML tylko troche, dlatego mam taki klopot.
dzieki wielkie za help krok po kroku dla poczatkujacych ;-)