mam problem.
Cytat
$result = mysql_query("SELECT FILE_NAME FROM upload_data WHERE USER_ID='$id' AND TYP='$typ' LIMIT 0,1");
if(mysql_num_rows($result)){
echo '<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple/>
<input type="submit"/>
</form>';
}
else {
?
}
if(mysql_num_rows($result)){
echo '<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple/>
<input type="submit"/>
</form>';
}
else {
?}
Co wpisac w
, aby otrzymac w echo FILE NAME?Nie moge sobie z tym poradzic.