select @idnr as nr from (SELECT @nr:=@nr+1,if(ID=@id, @idnr := @nr,@idnr=@idnr),ID FROM `users` order by `points` DESC)
zwraca błąd:
You have an error IN your SQL syntax; CHECK the manual that corresponds TO your MySQL server version FOR the RIGHT syntax TO USE near 'select @idnr as nr from (SELECT @nr:=@nr+1,if(ID=@id, @idnr := @nr,@idnr=@idn' at line 2
a jak wkleje to zapytanie w PhpMyAdminie w oknie SQL to wszystko ładnie przechodzi?