I mam błąd:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html> <head> <meta http-equiv="Content-type" content="text/html; charset=utf-8"> <title>Kamil Design - Poznaj internet na nowo</title> <link rel="stylesheet" href="style.css" type="text/css"> </head> <body> <?php include("include/config.php"); $sumbit = $_POST['sumbit']; $nick = $_POST['nick']; } else { $zapytanie = "SELECT * FORM users WHERE nick='$nick' AND haslo='$haslo';"; $login = $dane['login']; $haslo2 = $dane['haslo']; $poziom = $dane['poziom']; $_SESSION['username'] = $login; $_SESSION['userpass'] = $haslo2; $_SESSION['useracces'] = $poziom; } } ?> </body> </html>
mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/portalsi/public_html/moje_strony/portfolio/dzialy/loguj.php on line 22