Witam mam taki problem poniewaz nie wiem jak pobrac rekord z przed 5 godzin w bazie mam datetime

[PHP] pobierz, plaintext 
SELECT * FROM cos WHERE date=NOW();
[PHP] pobierz, plaintext 

pobiera mi całosc nie wiem jak uwzglednic te godziny

bede wdzieczny za pomoc

Manual:
http://dev.mysql.com/doc/refman/5.1/en/dat...-functions.html


Tak ciężko wpisać w google date mysql ?

Ja bym to zrobil na mktime, to kilka przykladow:

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//YESTERDAY
$yesterday = date("Y-m-d H:i:s",mktime(0, 0, 0, date("m")  , date("d")-1, date("Y")));
 
//THIS WEEK
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, date("n"), date("j"), date("Y")) - ((date("N")-1)*3600*24));
$toDate = CURRENT_TIMESTAMP;
//LAST WEEK
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, date("n"), date("j")-6, date("Y")) - ((date("N"))*3600*24));
$toDate = date("Y-m-d H:i:s",mktime(23, 59, 59, date("n"), date("j"), date("Y")) - ((date("N"))*3600*24));
 
//THIS MONTH
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, date("m")  , 1, date("Y")));
$toDate = CURRENT_TIMESTAMP;
 
//LAST MONTH
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, date("m")-1  , 1 , date("Y")));
$toDate = date("Y-m-d H:i:s",mktime(23, 59, 59, date("m"), date("d")-date("j"), date("Y")));
 
//THIS YEAR
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, date(1)  , date(1), date("Y")));
$toDate = CURRENT_TIMESTAMP;
 
//LAST YEAR
$fromDate = date("Y-m-d H:i:s",mktime(0, 0, 0, 1  , 1, date("Y")-1));
$toDate = date("Y-m-d H:i:s",mktime(23, 59, 59, 12, 31, date("Y")-1));
 
?>
 
 
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tak bym sprowadzil do zmiennej date z -5 godzin a tak bym wylosowal i przerobil date z bazy danych:

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$dbdat = explode("/", $row['op_date']); 
$dbyear = explode(" ", $dbdat[2]); 
$dbdate = $dbdat[0] . "/" . $dbdat[1] . "/". $dbyear[0];
$dbdateUnix = mktime(0,0,0,$dbdat[1],$dbdat[0],$dbyear[0]);
 
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gdzie $row['op_date'] to data pobrana w petli z bazy. potem pozostaje tylko if i po sprawie

[SQL] pobierz, plaintext 
WHERE DATA >= DATE_SUB(NOW(),INTERVAL 5 MINUTES) 
[SQL] pobierz, plaintext