Witam czy ktos moze mi pomoc rozwiazac problem z bledem mysql? probuje znalezc ale nie moge nic wskurac ;/

[PHP] pobierz, plaintext 
<?php
 
$connect = mysql_connect('lxxxt', 'xxx', 'xxx') or die(mysql_error());
mysql_select_db(xxx);
 
$id = $_GET['id'];
$query = "SELECT * FROM emes_content WHERE id = $id";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result);
echo '<h2>';
echo $row['title'];
echo '</h2>';
echo '<br><br>';
echo $row['content'];
 
if(!isset($_GET['id'])){
$query = "SELECT * FROM emes_content WHERE id = 1";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result);
echo '<h2>';
echo $row['title'];
echo '</h2>';
echo '<br><br>';
echo $row['content'];
}
 
?>
[PHP] pobierz, plaintext 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

ten skrypt nie sprawdza, czy dane wchodzące są prawidłowe (mam na myśli $_GET['id'])

Forum nie parser.